wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 20 kg ball is thrown upwards with a speed of 6m/s. Find its potential energy when it reaches the highest point. Also, find the maximum height it reaches (g=9.8 ms2).

A
0.22 m,88.2 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.45 m,176.4 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.9 m,264.6 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.8 m,352.8 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1.8 m,352.8 J
Using 3rd Equation of motion
v2=u22gh
0=622×9.8×h
h=1.837 m (approx.)

Potential Energy at highest point =mgh
=20×9.8×1.837
=360 J

So, there is not any option exactly matching. But, for the given options, (D) is the most suitable

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Realistic Collisions
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon