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Question

A 20 kg block is initially at rest. a 75 N force is required to set the block in motion. after the motion a force of 60 N is applied to keep the block moving with constant speed. the coefficient of static friction

A
0.6
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B
0.52
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C
0.44
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D
0.37
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Solution

The correct option is B 0.37
As 75N force is required to set the block in motion that means maximum value of static friction is
75N
So, μsmg=75
μs=0.37

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