A 20kg block is placed on top of 50kg block as shown in the figure. A horizontal force F acting on A produces an acceleration of 3m/s2 in A and 2m/s2 in B as shown in the figure. For this situation, choose the correction option(s).
A
The friction force between A and B is 40N.
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B
The net force acting on A is 150N.
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C
The value of F is 190N.
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D
The value of F is 150N.
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Solution
The correct options are A The friction force between A and B is 40N. B The net force acting on A is 150N. C The value of F is 190N.
Using the FBD of the block B, Friction force on block B, f=mBaB=20×2=40N Using the FBD of the block A, F−f=mAaA=50×3=150N F=150+40=190N