CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 20 kg body is pushed with just enough force to start it moving across a floor and the same force continues to act afterwards. The coefficient of static and kinetic friction are 0.6 & 0.2 respectively. The acceleration of the body is :

A
6 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4 m/s2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 4 m/s2
The force needed to start the motion is nothing but static friction which is μmg so the force applied is μmg ;μ=0.6 so force is 0.6mg
Now once the body comes in motion the friction changes to kinetic so friction now is 0.2mg and it will oppose the motion.

So net force on the body will be Applied Force-Kinetic friction=0.6mg0.2mg=0.4mg
So acceleration will be NetForce/mass=0.4mg/m=0.4g=0.4×10=4m/s2
Option D is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon