A 20kg body is pushed with just enough force to start it moving across a floor and the same force continues to act afterwards. The coefficient of static and kinetic friction are 0.6 & 0.2 respectively. The acceleration of the body is :
A
6m/s2
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B
1m/s2
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C
2m/s2
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D
4m/s2
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Solution
The correct option is D4m/s2 The force needed to start the motion is nothing but static friction which is μmg so the force applied is μmg ;μ=0.6 so force is 0.6mg
Now once the body comes in motion the friction changes to kinetic so friction now is 0.2mg and it will oppose the motion.
So net force on the body will be Applied Force-Kinetic friction=0.6mg−0.2mg=0.4mg
So acceleration will be NetForce/mass=0.4mg/m=0.4g=0.4×10=4m/s2