Question

A $20kg$ body is suspended by strings $a$ and $b$ as shown.
Find the tension in $a$ and $b(20/\sqrt{3}kg$ wt. each).

Answer 1

assume that tension in string $a$ is $T_a$ and in string $b$ is $T_b$

now taking the component of tensions

$T_a\sin {30}^{\circ }=T_b\sin {30}^{\circ }...\left(1\right)$

it means $T_a$$=T_b$

$T_a\cos {30}^{\circ }+T_b\cos {30}^{\circ }=mg...\left(2\right)$

$\Rightarrow 2T_a\cos {30}^{\circ }=20\times 10\Rightarrow T_a=T_b=\frac{200}{\sqrt{3}}N$