A 20 kg object is lifted through a height of ______ m when 784 J of work is done on it.
[Assume $g = 9.8 m / s^{2}$ ]

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7.84

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3.92

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Solution

The correct option is B 4
Work, $W = m g h$
$h = \frac{W}{m g} = \frac{784}{20 \times 9.8} = 4 m$

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