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Byju's Answer

Standard XII

Chemistry

Concentration Terms - An Introduction (w/w etc)

A 20 mL sam...

Question

A $20 m L$ sample of a $B a (O H)_{2}$ solution is titrated with $0.245 M H C l$ . If $27.15 m L$ of $H C l$ is required, what is the molarity of the $B a (O H)_{2}$ solution?

0.166 M

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0.180 M

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0.333 M

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0.666 M

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Solution

The correct option is A $0.166 M$
Hence option A is correct.

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Similar questions

20 g

of a sample of

B a (O H)_{2}

is dissolved in

10 m L

0.5 N H C l

solution. The excess of

H C l

was titrated with

0.2 N N a O H .

The volume of

N a O H

required was

10 m L

. Calculate the percentage of

B a (O H)_{2}

in the sample.
(Given molar mass of

B a

137 g m o l^{- 1}

)

20 g

of a sample of

B a (O H)_{2}

is dissolved in

10 m L

0.5 N H C l

solution. The excess of

H C l

was titrated with

0.2 N N a O H .

The volume of

N a O H

required was

10 m L

. Calculate the percentage of

B a (O H)_{2}

in the sample.
(Given molar mass of

B a

137 g m o l^{- 1}

)

10 g

of a sample of

B a (O H)_{2}

is dissolved in

10 m L

0.5 N

H C l

solution. The excess of HCl was titrated with

0.2 N

N a O H

. The volume of

N a O H

used was

20 c c

. Calculate the percentage of

B a (O H)_{2}

in the sample.

Q. What

[{O H}^{-}]

in the final solution prepared by mixing

20 m L

0.05 M

H C l

with

30 m L

0.10 M

B a {(O H)}_{2}

Q. A

0.2 g

sample of benzoic acid,

C_{6} H_{5} C O O H

, is tritated with a

0.120 M B a (O H)_{2}

solution. What volume of the

B a (O H)_{2}

solution is required to reach the equivalent point?

\frac{S u b s t a n c e}{C_{6} H_{5} C O O H} \frac{M o l a r m a s s}{122.1 g m o l^{- 1}}

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A 20 mL sample of a Ba(OH)2 solution is titrated with 0.245 M HCl. If 27.15 mL of HCl is required, what is the molarity of the Ba(OH)2 solution?

The correct option is A 0.166 MHence option A is correct.

A $20 m L$ sample of a $B a (O H)_{2}$ solution is titrated with $0.245 M H C l$ . If $27.15 m L$ of $H C l$ is required, what is the molarity of the $B a (O H)_{2}$ solution?

The correct option is A $0.166 M$
Hence option A is correct.