Question

A $20$ $\Omega$ square loop is placed in uniform 3.6 T magnetic field perpendicular to plane of loop, where each ends are moving with speed 1 m/s, find avarage induced emf at t = 1.2 sec ?

• A. 48 $V$
• B. 36 $V$
• C. 24 $V$
• D. 6 $V$

Answer 1

The correct option is A 48 $V$

${\varphi }_1=B.A=\left(3.6\right)\{4\times 4\}$
= $16\times 3.6$
$\Delta \varphi =16\times 3.6$
$e=\frac{\Delta \varphi }{\Delta t}=\frac{16\times 3.6}{1.2}=48V$