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Question

A 20 kg block is placed on top of 50 kg block as shown in figure. A horizontal force F acting on A causes an acceleration of 3 m/s2 to A and 2 m/s2 to B as shown in figure. For this situation mark out the correct statement(s).

A
The friction force between A and B is 40 N
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B
The net force acting on A is 150 N
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C
The value of F is 190 N
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D
The value of F is 150 N
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Solution

The correct options are
A The friction force between A and B is 40 N
B The net force acting on A is 150 N
C The value of F is 190 N
There is a relative motion between A and B since there accelerations are different.
For A,
Writing Newton's second law
Fnet=mAaA
Ff=mAaA=50×3=150 N

For B1,
f=mBaB=20×2=40 N

Net force on A is Ff=150 N
F=150+40=190 N

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