CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Molecular Mass

A 20 mL solut...

Question

A $20 mL$ solution of hydrogen peroxide reacts quantitatively with a $20 mL$ solution of $K M n O_{4}$ acidified with dilute $H_{2} S O_{4}$ . The same volume of the $K M n O_{4}$ solution is decolourised by $10 mL$ of $M n S O_{4}$ in neutral medium simultaneously forming a dark brown precipitated of hydrated $M n O_{2}$ . The brown precipitate is dissolved in $20 mL$ of $0.2 M$ sodium oxalate under boiling condition in the presence of dilute $H_{2} S O_{4}$ . Calculate the volume strength of $H_{2} O_{2}$ .

Open in App

Solution

$2 K M n O_{4} + 5 H_{2} O_{2} + 3 H_{2} S O_{4} \to 2 M n S O_{4} + K_{2} S O_{4} + 8 H_{2} O + 5 O_{2} 2 K M n O_{4} + 3 M n S O_{4} + 2 H_{2} O_{2} \to 5 M n O_{2} + 2 H_{2} S O_{4} + K_{2} S O_{4} M n O_{2} + N a_{2} C_{2} O_{4} + 2 H_{2} S O_{4} \to M n S O_{4} N a_{2} S O_{4} + 2 H_{2} O + 2 H_{2} O + 2 C O_{2}$
$∴ Miliequivalents of M n O_{2} = Miliequivalents of N a_{2} C_{2} O_{4} = Miliequivalents of K M n O_{4} = Miliequivalents of H_{2} O_{2} = 20 \times 0.2 \times 2 = 8 ∴ N_{H_{2} O_{2}} \times 20 = 8 \Rightarrow N_{H_{2} O_{2}} = 0.4$
$Volume strength of H_{2} O_{2} = 5.6 \times N_{H_{2} O_{2}}$
$= 5.6 \times 0.4 = 2.24$

Suggest Corrections

thumbs-up

0

Similar questions

Hydrogen peroxide solution (

20

mL) reacts quantitatively with a solution of

K M n O_{4}

20

mL) acidified with dilute

H_{2} S O_{4}

. The same volume of the

K M n O_{4}

solution is just decolourised by

10

M n S O_{4}

in neutral medium simultaneously forming a dark brown precipitate of hydrated

M n O_{2}

. The brown precipitate is dissolved in

10

0.2 M

sodium oxalate under boiling condition in the presence of dilute

H_{2} S O_{4}

Choose the correct balanced equation involved in the reaction.

Q. Hydrogen peroxide solution having volume of

20

mL reacts quantitatively with a solution of

K M n O_{4}

20

mL acidified with dilute

H_{2} S O_{4}

. The same volume of the

K M n O_{4}

solution is just decolourised by

10

M n S O_{4}

in a neutral medium simultaneously forming a dark-brown precipitate of hydrated

M n O_{2}

. The brown precipitate is dissolved in

10

0.2 M

sodium oxalate under boiling condition in the presence of dilute

H_{2} S O_{4}

. If the molarity of

H_{2} O_{2}

x

, then find the value of

10 x

Q. Hydrogen peroxide solution (20 mL) reacts quantitatively with a solution of

K M n O_{4}

(20 mL) acidified with dilute

H_{2} S O_{4}

, The same volume of the

K M n O_{4}

solution is just decolorized by 10mL of

M n S O_{4}

in neutral medium simultaneously forming a dark brown precipitate of hydrated

M n O_{2}

The brown pecipitate is dissolved in 10 mL of 0.2 M sodium oxalate under boiling condition in the presence of dilute

H_{2} S O_{4}

, Write the balanced equations involved in the reactions and calculate the molarity of

H_{2} O_{2}

Q. Hydrogen peroxide solution

(20 m L)

reacts quantitatively with a solution of

K M n O_{4} (20 m L)

acidified with dilute

H_{2} S O_{4}

. The same volume of the

K M n O_{4}

solution is just decolourised by

10 m L

M n S O_{4}

in neutral medium simultaneously forming a dark brown precipitate of hydrated

M n O_{2}

. The brown precipitate is dissolved in

10 m L

0.2 M

sodium oxalate under boiling condition in the presence of dilute

H_{2} S O_{4}

. Write the balanced equations involved in the reactions and calculate the molarity of

H_{2} O_{2}

10

mL of a solution of

H_{2} O_{2}

10

volume strength decolourises

100

K M n O_{4}

solution acidified with dil.

H_{2} S O_{4}

. The amount of

K M n O_{4}

in the given solution is (

K = 39, M n = 55

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Molecular Mass

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard X Chemistry

Join BYJU'S Learning Program

CrossIcon