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Question

# A 20 N metal block is suspended by a spring balance. A beaker containing some water is placed on a weighing machine which reads 40 N. The spring balance is now lowered slowly into the beaker such that the block gets immersed in the water. The spring balance now reads 16 N. The reading of the weighing machine will be

A
36 N
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B
60 N
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C
44 N
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D
56 N
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Solution

## The correct option is C 44 NLoss in weight of block after being immersed in water is, ΔW=20−16=4 N This decrease in weight is due to buoyant force by water acting on the block in vertically upward direction. ⇒Fb=ΔW=4 N According to Newton's 3rd law, block will apply equal amount of force (i.e Fb) on water in downward direction. ⇒ Reading of weighing machine is given by, WM=Initial reading+Fb ∴WM=40+4=44 N

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