1
Question
A 200 bus power system has 160 PQ buses. To obtain the load flow solution by using Newton Raphson method in polar coordinates, the minimum number of simultaneous equations to be solved is _______.
- 359
- 359
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Solution
The correct option is A 359
Total buses = 200
PQ buses = 160
generator buses (PV) = 200 - 160 = 40 buses
among 40 PV buses one have to choose as slack bus.
The remaining generator buses = 39
Total no. of equations = 2PQ+PV = (160 × 2) + (39 × 1)
= 359
Total buses = 200
PQ buses = 160
generator buses (PV) = 200 - 160 = 40 buses
among 40 PV buses one have to choose as slack bus.
The remaining generator buses = 39
Total no. of equations = 2PQ+PV = (160 × 2) + (39 × 1)
= 359
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