A $200 g$ mass is whirled in a vertical circle making $60$ revolutions per minute. What is the tension in the string at the top of the circle if the radius of the circle is $0.8 m$ ? (in $N$ )

6.3

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2.36

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4.35

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4.23

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Solution

The correct option is C $4.35$
$w = 60 revolutions per minute = 60 * 2 π / 60 rad/ sec = 2 π r a d / s e c$
$200 g m = 0.2 k g$
$T = m r w^{2} - m g$
$T = 0.2 * 0.8 * (2 π)^{2} - 0.2 * 9.8$
$T = 4.35 N$

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A 200g mass is whirled in a vertical circle making 60 revolutions per minute. What is the tension in the string at the top of the circle if the radius of the circle is 0.8m? (in N)

The correct option is C 4.35w=60 revolutions per minute =60∗2π/60 rad/ sec=2π rad/sec200gm=0.2kgT=mrw2−mgT=0.2∗0.8∗(2π)2−0.2∗9.8T=4.35N

A $200 g$ mass is whirled in a vertical circle making $60$ revolutions per minute. What is the tension in the string at the top of the circle if the radius of the circle is $0.8 m$ ? (in $N$ )

The correct option is C $4.35$
$w = 60 revolutions per minute = 60 * 2 π / 60 rad/ sec = 2 π r a d / s e c$
$200 g m = 0.2 k g$
$T = m r w^{2} - m g$
$T = 0.2 * 0.8 * (2 π)^{2} - 0.2 * 9.8$
$T = 4.35 N$