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Question

A 200 g sample of hard water is passed through the column of cation exchange resin in which H+ is exchanged by Ca2+. The outlet water of column required 50 mL of 0.1MNaOH for complete neutralization. What is the hardness of Ca2+ ion in ppm?

A
250 ppm
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B
500 ppm
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C
750 ppm
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D
1000 ppm
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Solution

The correct option is B 500 ppm
Milli-moles of H+ present in outlet water = Milli-moles of OH=50×0.1=5
Milli-moles of Ca2+ present in hard water=52=2.5 (1Ca2+ replaced by 2H+)
Number of mg of Ca2+ ion=2.5×40=100
200 g sample hard water contain 100 mg of Ca2+.
106 g sample hard water contain 100200×106×103=500 ppm.

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