A $200 k g$ motorcycle is driven around a $14 m$ radius horizontal circular loop at a constant speed of $15 m / s$ . Calculate the required centripetal force on the motorcycle.

$F = 321 N$

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$F = 3214.3 N$

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$F = 1214.3 N$

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$F = 3614.3 N$

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Solution

The correct option is B
$F = 3214.3 N$

Given: $mass m = 200 kg, radius r = 14 m, velocity v = 15 m/s, Force = ?$

We know that, centripetal force $F$ = $\frac{m v ²}{r}$

So, $F$ = $\frac{200 * 15 ²}{14}$

i.e. $F = 3214.3 N$

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A 200 kg motorcycle is driven around a 14 m radius horizontal circular loop at a constant speed of 15 m/s. Calculate the required centripetal force on the motorcycle.

The correct option is B F = 3214.3 N Given: mass m = 200 kg, radius r = 14 m, velocity v = 15 m/s, Force = ? We know that, centripetal force F = mv²r So,F = 200∗15²14 i.e. F = 3214.3 N

A $200 k g$ motorcycle is driven around a $14 m$ radius horizontal circular loop at a constant speed of $15 m / s$ . Calculate the required centripetal force on the motorcycle.

The correct option is B
$F = 3214.3 N$

Given: $mass m = 200 kg, radius r = 14 m, velocity v = 15 m/s, Force = ?$

We know that, centripetal force $F$ = $\frac{m v ²}{r}$

So, $F$ = $\frac{200 * 15 ²}{14}$

i.e. $F = 3214.3 N$