A $200$ metre long train passes a motorcycle, running in the same direction at $12$ kmph, in $15$ seconds and a car travelling in the same direction in $20$ seconds. At what speed is the car travelling (length of both the motorcycle and car is negligible)?

36

kmph

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24

kmph

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48

kmph

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60

kmph

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Solution

The correct option is B $24$ kmph
Let the speed of the train be $R$ kmph
From the given data,
Distance $=$ Length of train $= D = 200$ m $= \frac{1}{5}$ km
Given speed of the motorcycle $= 12$ kmph
Relative speed as they are moving in the same direction $= (R - 12)$ kmph
Train passes the motorcycle in $15$ sec $= \frac{15}{3600}$ hr
$∴ \frac{1}{5} = \frac{15}{3600} (R - 12)$
$\Rightarrow R - 12 = 48$
$\Rightarrow R = 60$ kmph

Now,
Let the speed of the car be $x$ kmph.
Train passes the car in $20$ sec $= \frac{20}{3600}$ hr
$∴ \frac{1}{5} = \frac{20}{3600} (60 - x)$
$\Rightarrow 60 - x = 36$
$\Rightarrow x = 24$
Therefore, speed of the car, $x = 24$ kmph.

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A 200 metre long train passes a motorcycle, running in the same direction at 12 kmph, in 15 seconds and a car travelling in the same direction in 20 seconds. At what speed is the car travelling (length of both the motorcycle and car is negligible)?

A $200$ metre long train passes a motorcycle, running in the same direction at $12$ kmph, in $15$ seconds and a car travelling in the same direction in $20$ seconds. At what speed is the car travelling (length of both the motorcycle and car is negligible)?