A 2000 kg automobile is travelling at 54 kmph. Find the average force to stop it in 25 m.

9000

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5000

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1000

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500

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Solution

The correct option is A 9000
Given that,
Mass 'm' $= 2000$ kg
Initial velocity $v_{1} = 54 k m / h = \frac{54 \times 1000}{60 \times 60} = 15 m / s$
Distance 'd' $= 25$ m
Final velocity $v_{f} = 0$
$\begin{matrix} v_{f}^{2} - v_{i}^{2} = 2 a d 0 - 225 = 2 a \times 25 a = - \frac{9}{2} m / s^{2} \end{matrix}$
Therefore the deceleration $- 4.5 m / s^{2}$
$F = m a s s \times d e c e l e r a t i o n$
$F = 2000 \times 4.5 = 9000 N$
Hence, Option $A$ is correct.

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