A $200 m$ long train crosses a $1400 m$ long bridge with a uniform speed of $72 k m / h$ . Calculate the time taken by the train to cross the bridge?

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Solution

Step 1. Given:
Length of the train [L]= $200 m$
Length of the bridge [l]= $1400 m$
Total distance covered by the train[s] = $L + l = 1400 + 200 = 1600 m$
Speed of train [v]= $72 k m / h$
$v = 72 k m / h v = 72 \times 1000 / 60 \times 60 v = 20 m / s$
Formula Used: $S p e e d [v] = d i s \tan c e / t i m e$
Step2 :Final solution:
To find the time.
$S p e e d [v] = \frac{d i s \tan c e [s]}{t i m e [t]} t = \frac{s}{v} = \frac{1600}{20} = 80 s e c o n d s$
Hence the total time taken by the train to cross the bridge is 80seconds.

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