$A (- 2, 2), B (8, 2)$ and $C (4, - 4)$ are the vertices of a parallelogram $A B C D$ . Find the other vertex and the area of the parallelogram.

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Solution

Area of the parallelogram $A B C D = b a s e \times a l t i t u d e = C D \times A E$

$= 10 \times 6 = 60$ sq.untis

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Question 2
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