A 220 V, 1000 W bulb is connected across a 110 V mains supply. The power consumed will be

750 W

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500 W

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250 W

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1000 W

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Solution

The correct option is C 250 W
Resistance of the bulb = $\frac{V^{2}}{W} = \frac{220^{2}}{1000} = 48.4 Ω$
Now, at 110 V supply,
Power consumed = $\frac{V^{2}}{R} = \frac{110^{2}}{48.4} = 250 W$

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A 220 V, 1000 W bulb is connected across a 110 V mains supply. The power consumed will be

The correct option is C 250 WResistance of the bulb = V2W=22021000=48.4Ω Now, at 110 V supply, Power consumed = V2R=110248.4=250W

The correct option is C 250 W
Resistance of the bulb = $\frac{V^{2}}{W} = \frac{220^{2}}{1000} = 48.4 Ω$
Now, at 110 V supply,
Power consumed = $\frac{V^{2}}{R} = \frac{110^{2}}{48.4} = 250 W$