Question

A 220 volt and 800 watt electric kettle and three 220 volt and 100 watt bubs are connected in parallel. On connecting this combination with 220 volt electric supply, the total current will be

• A. $0.15$ ampere
• B. $5.0$ ampere
• C. $5.5$ ampere
• D. $6.9$ ampere

Answer 1

The correct option is B $5.0$ ampere

Power = Current x Voltage

$P=VI$

Given $P_1=800W$

$P_2=3\times 100$

so Total power $P=(800+3\times 100)$ Also $P=Vi\Rightarrow 1100=220\times i\Rightarrow i=5A$