Question

$A(2,3),B(3,1)$,and $C(5,3)$ are three points,then the slope of the line passing through $A$ and bisecting $BC$ is -

• A. $\frac{1}{2}$
• B. $-2$
• C. $-\frac{1}{2}$
• D. $2$

Answer 1

The correct option is D $2$

$A(2,3)B(3,1)C(5,3)$

Mid point of $BC(\frac{3+5}{2},\frac{1+3}{2})$

$x(4,2)$

Equation of the line passing through $A(2,3)$ and $x(4,2)$

$y-3=\frac{2-3}{4-2}(x-2)$

$2y-6=x-2$

$x-2y+4=0$

Slope $\frac{-b}{a}=\frac{-(-2)}{1}=2$.