CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 230 V, 50 Hz, 4-pole single-phase split phase induction motor is tested to yield the following results (with auxiliary winding open):
No load test : 230 V, 6.4 A, 220 W
Block rotor test : 82.5 V, 9.3 A, 500 W
The main winding resistance is 2.5 Ω, then the rotor resistance referred to stator is ________Ω.

A
8.87 Ω
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3.28 Ω
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
6.73 Ω
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5.78 Ω
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 3.28 Ω
Impedance under block rotor condition,
Zb=VbIb=82.59.3=8.87 Ω
Resistance under block rotor condition,
Rb=WbI2b=500(9.3)2=5.78 Ω
Rotor resistance referred to stator,
R2=RbR1
=5.782.5=3.28 Ω

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Self and Mutual Inductance
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon