A 25 L sample of nitrogen is heated from 110- C to 260- C- What volume will the sample occupy at the higher temperature-A- 24-79 LB- 54-79 LC- 44-79 LD- 34-79 L

The correct option is D 34.79 L According to Charles' Law, V_1/T_1 = V_2/T_2 where V_1=25 L :T_1=110^∘ C=(273+110)K= 383 K : T_2=260^∘ C=(273+260)K= 533 K ⇒ T ...

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Byju's Answer

Standard X

Physics

Charles Law

A 25 L sample...

Question

A 25 L sample of nitrogen is heated from $110^{\circ}$ C to $260^{\circ}$ C. What volume will the sample occupy at the higher temperature?

54.79 L

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24.79 L

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44.79 L

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34.79 L

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Solution

The correct option is D
34.79 L

According to Charles' Law,

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

where $V_{1} = 25 L : T_{1} = 110^{\circ} C = (273 + 110) K = 383 K :$

$T_{2} = 260^{\circ} C = (273 + 260) K = 533 K$

$\Rightarrow T_{2} = \frac{V_{2} T_{1}}{V_{1}}$

$\Rightarrow T_{2} = \frac{25 \times 533}{383} = 34.79$

Hence, the final volume= 34.79 L

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A 25 L sample of nitrogen is heated from 110∘ C to 260∘C. What volume will the sample occupy at the higher temperature?

The correct option is D 34.79 L According to Charles' Law, V1T1=V2T2 where V1=25 L :T1=110∘C=(273+110)K=383 K : T2=260∘C=(273+260)K=533 K ⇒T2=V2T1V1 ⇒T2=25×533383=34.79 Hence, the final volume= 34.79 L

A 25 L sample of nitrogen is heated from $110^{\circ}$ C to $260^{\circ}$ C. What volume will the sample occupy at the higher temperature?