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Question

A 25 mm diameter horizontal pipe has a neck of 18 mm diameter. water flows in the broader point of pipe at 1.8 m/s. What is the speed of water in the neck? What is the 1. volume 2. mass flow rate?
(3.5m/s1.88×104m3/s2.0.88kg/s)

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Solution

By equation of continuity flow
AV = constant
A1V1=A2V2
(πr21)V1=(πr22)V2

(25)2×1.8m/sec=(18)2×V2

V2=62518×18×1.810

=12536 m/sec

V2=3.5 m/sec

Volume flow rate =A1V1
=π(25×103)2×1.8
=0.0035m2/sec

Volume state =(πR21)V1

V=3.14×(252×103)2×1.8

=88×104m3/sec

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