A 25 mm diame...

Question

A 25 mm diameter horizontal pipe has a neck of 18 mm diameter. water flows in the broader point of pipe at 1.8 m/s. What is the speed of water in the neck? What is the 1. volume 2. mass flow rate?
$(3.5 m / s 1.88 \times 10^{- 4} m^{3} / s 2.0.88 k g / s)$

Open in App

Solution

By equation of continuity flow
$A V$ = constant
$A_{1} V_{1} = A_{2} V_{2}$
$\Rightarrow (π r_{1}^{2}) V_{1} = (π r_{2}^{2}) V_{2}$

$\Rightarrow (25)^{2} \times 1.8 m / s e c = (18)^{2} \times V_{2}$

$\Rightarrow V_{2} = \frac{625}{18 \times 18} \times \frac{1.8}{10}$

$= \frac{125}{36}$ m/sec

$V_{2} = 3.5$ m/sec

Volume flow rate $= A_{1} V_{1}$
$= π (25 \times 10^{- 3})^{2} \times 1.8$
$= 0.0035 m^{2} / s e c$

Volume state $= (π R_{1}^{2}) V_{1}$

$V = 3.14 \times {(\frac{25}{2} \times 10^{- 3})}^{2} \times 1.8$

$= 88 \times 10^{- 4} m^{3} / s e c$

Suggest Corrections

Similar questions

(75.36 \times 10^{- 6} m^{3} / s; 24 c m / s)

80 \times 10^{- 3} (m^{3} / s e c)

10^{3} (k g / m^{3})

10^{- 3} (N s / m^{2})

60 m m

20 m m

50 k P a

(i n m / s

25^{\circ}

0.07 m^{3} / s

1000 k g / m^{3}

^{3}

^{3}

\times

^{- 3}