A 25 W -120 V bulb and a 100 W -120 V bulb are connected in series across a 120 V line- Which bulb will glow brighter- A- 25 W -120 VB- 100 W -120 VC- both will have same incandescenceD- Neither will give any light

The correct option is A 25 W nbsp; 120 V R_1 = (120)^225 , R_2 = (120)^2100 are bulb resistances. Since, nbsp; R_1 gt; R_2 P_1 = i^2 R_1, P_2 = i^2 ...

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Standard XII

Physics

Power in Electric Circuits

A 25 W -120 V...

Question

A $25 W - 120 V$ bulb and a $100 W - 120 V$ bulb are connected in series across a $120 V$ line. Which bulb will glow brighter?

25 W - 120 V

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100 W - 120 V

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both will have same incandescence

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Neither will give any light

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Solution

The correct option is A $25 W - 120 V$

$R_{1} = \frac{(120)^{2}}{25}, R_{2} = \frac{(120)^{2}}{100}$ are bulb resistances. Since, $R_{1} > R_{2}$

$P_{1} = i^{2} R_{1}, P_{2} = i^{2} R_{2}$

$\Rightarrow P_{1} > P_{2}$

$\Rightarrow$ Bulb $1$ will glow brighter.

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A 25 W−120 V bulb and a 100 W−120 V bulb are connected in series across a 120 V line. Which bulb will glow brighter?

The correct option is A 25 W−120 V R1=(120)225,R2=(120)2100 are bulb resistances. Since, R1>R2 P1=i2R1,P2=i2R2 ⇒P1>P2 ⇒Bulb 1 will glow brighter.

A $25 W - 120 V$ bulb and a $100 W - 120 V$ bulb are connected in series across a $120 V$ line. Which bulb will glow brighter?

The correct option is A $25 W - 120 V$

$R_{1} = \frac{(120)^{2}}{25}, R_{2} = \frac{(120)^{2}}{100}$ are bulb resistances. Since, $R_{1} > R_{2}$

$P_{1} = i^{2} R_{1}, P_{2} = i^{2} R_{2}$

$\Rightarrow P_{1} > P_{2}$

$\Rightarrow$ Bulb $1$ will glow brighter.