A 250- Turn rectangular coil of length 2.1 cm and width 1.25 cm carries a current of 85 μA and subjected to a magnetic field of strength 0.85 T. Work done for rotating the coil by 1800 against the torque is:
Given that,
Length, l=2.1cm
Width, W=1.25cm
Current, i=85μA
Magnetic field, B=0.85T
Work done in rotating the coil is given by:
W=MB(cosθ1−cosθ2)
W=MB(cos0−cos180)
W=2MB
W=2(NIA)B
W=2×250×85×10−6×(1.25×2.1×10−4)×85×10−2
W=9482812.5×10−12
W=9.4μJ