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Question

A 27oC one mole of an ideal gas is compressed isothermally and reversible from the pressure of 2 atm to 10 atm. The value of and ΔE and q are:


[R=2 cal]

A
0,965.84 cal
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B
965.84 cal, 865.58 cal
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C
+865.58 cal, 865.58 cal
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D
+965.84 cal, +865.58 cal
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Solution

The correct option is A 0,965.84 cal
Isothermal (at constant temperature) and reversible work is given by,
W=2.303nRTlogP2P1
W=2.303× 1 mol× 2 cal/mol/K × 300 Klog102
W=2.303×600×log5
W=965.84 cal.
ΔE=q+W
At constant temperature, ΔE=0
0=q+W
q=W=965.84 cal.
Hence, option A is correct.

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