Question

A 280 ohm electric bulb is connected to 200V electric line. The peak value of current in the bulb will be

• A. About one ampere
• B. Zero
• C. About two ampere
• D. About four ampere

Answer 1

The correct option is A About one ampere

$i_{rms}=\frac{200}{280}=\frac{5}{7}A$. So $i_0=i_{rms}\times \sqrt{2}=\frac{5}{7}\times \sqrt{2}\approx 1A$.