$(a + 2 b)^{2} - 8 a b$ is equal to

a^{2} + 4 b^{2}

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a^{2} - 4 b^{2}

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(a - 2 b)^{2}

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a^{2} + 2 b^{2}

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Solution

The correct option is C $(a - 2 b)^{2}$
$(a + 2 b)^{2} - 8 a b = a^{2} + 4 b^{2} + 4 a b - 8 a b$
$= a^{2} + 4 b^{2} - 4 a b$
$= (a)^{2} + (2 b)^{2} - 2 (a) (2 b)$
$= (a - 2 b)^{2}$

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