A 2cm tall object is placed 15 CM in front of a concave mirror of focal length 10cm what is the size and nature of the image

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Dear Student
$u = - 15 c m, f = - 10 c m \frac{1}{v} + \frac{1}{u} = \frac{1}{f} \frac{1}{v} = \frac{- 1}{10} + \frac{1}{15} v = - 30 c m m a g n i f i c a t i o n = \frac{- v}{u} = + 2 m = \frac{h e i g h t o f i m a g e}{h e i g h t o f o b j e c t} h e i g h t o f i m a g e = 2 \times 2 = 4 c m R E G A R D S$

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A 2cm tall object is placed 15 CM in front of a concave mirror of focal length 10cm what is the size and nature of the image

Dear Student u=-15cm ,f=-10cm1v+1u=1f1v=-110+115v=-30cmmagnification=-vu=+2m=height of imageheight of objectheight of image=2×2=4cmREGARDS