1
Question
A 3.0 cm wire carrying
a current of 10 A is placed inside a solenoid perpendicular to its
axis. The magnetic field inside the solenoid is given to be 0.27 T.
What is the magnetic force on the wire?
A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?
Open in App
Solution
Length of the wire, l
= 3 cm = 0.03 m
Current flowing in the
wire, I = 10 A
Magnetic field, B
= 0.27 T
Angle between the
current and magnetic field, θ = 90°
Magnetic force exerted
on the wire is given as:
F
= BIlsinθ
=
0.27 × 10 × 0.03 sin90°
=
8.1 × 10–2
N
Hence, the magnetic
force on the wire is 8.1 × 10–2 N. The
direction of the force can be obtained from Fleming’s left hand
rule.
Length of the wire, l = 3 cm = 0.03 m
Current flowing in the wire, I = 10 A
Magnetic field, B = 0.27 T
Angle between the current and magnetic field, θ = 90°
Magnetic force exerted on the wire is given as:
F = BIlsinθ
= 0.27 × 10 × 0.03 sin90°
= 8.1 × 10–2 N
Hence, the magnetic force on the wire is 8.1 × 10–2 N. The direction of the force can be obtained from Fleming’s left hand rule.
Suggest Corrections
0
Similar questions
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
