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Standard XII

Physics

Relation between Work Done and PE

A 3.0 N for...

Question

A $3.0 N$ force applied on a $0.40 k g$ mass makes the mass move at a constant speed of $3.0 m / s$ , held back by friction. In the span of it moving through $4.0 m$ , how much work does friction do on the given mass?

0 J

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0.90 J

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12 J

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- 12 J

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- 0.90 J

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Solution

The correct option is E $- 12 J$
Work done by $3.0 N$ force is ,
$W = f \times d = 3.0 \times 4.0 = 12 N$
as the speed is constant therefore net work done will be zero i.e. work done by friction will be equal to the work done by a $3.0 N$ force but in opposite direction , that is $- 12 N$ .

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A 3.0N force applied on a 0.40kg mass makes the mass move at a constant speed of 3.0m/s, held back by friction. In the span of it moving through 4.0m, how much work does friction do on the given mass?

The correct option is E −12JWork done by 3.0N force is , W=f×d=3.0×4.0=12Nas the speed is constant therefore net work done will be zero i.e. work done by friction will be equal to the work done by a 3.0N force but in opposite direction , that is −12N .

A $3.0 N$ force applied on a $0.40 k g$ mass makes the mass move at a constant speed of $3.0 m / s$ , held back by friction. In the span of it moving through $4.0 m$ , how much work does friction do on the given mass?

The correct option is E $- 12 J$
Work done by $3.0 N$ force is ,
$W = f \times d = 3.0 \times 4.0 = 12 N$
as the speed is constant therefore net work done will be zero i.e. work done by friction will be equal to the work done by a $3.0 N$ force but in opposite direction , that is $- 12 N$ .