Question

A(-3, -4) , B(3, 0) , C(-5, 0) are the vertices of $△$ABC. Find the co-ordinates of the circumcentre of $△$ABC.

• A. $(\frac{-1}{2},\frac{1}{2})$
• B. $(\frac{-1}{2},2)$
• C. $(2,\frac{1}{2})$
• D. $(-1,\frac{-1}{2})$

Answer 1

The correct option is D $(-1,\frac{-1}{2})$


Let $P(x,y)$ be the circumcentre of $△ABC$.
$\therefore$ Point $P$ is equidistant from $A,B\&C.$
$PA=PB=PC$
$P{A}^2=P{B}^2=P{C}^2---\left(i\right)$ [on squaring]