A(−3,4),B(5,4) are two vertices of a rectangle ABCD and 4y=x+7 is a diameter of the circle circumscribing ABCD. The width of the rectangle is
A
8
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B
6
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C
4
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D
2
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Solution
The correct option is C4 The midpoint of side AB of the rectangle has coordinates E:(−3+52,4+42)=(1,4). The equation of AB is y=4. Hence, equation of line passing through E and perpendicular to AB is x=1. x=1 will pass through the center. Also, the equation of one diameter is 4y=x+7. Hence, coordinates of center are point of intersection of x=1 and 4y=x+7. We get the coordinates of center O as (1,2). Width of rectangle is 2OE=2×2=4