A $3.7$ litre $1.0 M$ $N a O H$ solution is mixed with another $5$ litre $0.30 M$ $N a O H$ solution. The molarity of the resulting solution is:

0.80 M

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0.10 M

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0.73 M

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0.59 M

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Solution

The correct option is D $0.59 M$
$1.0 M N a O H$ means $1 m o l e N a O H$ in 1 litre.
Moles of $N a O H$ in $3.7 L = 1 \times 3.7 = 3.7 m o l e s$
$0.3 M N a O H$ means $0.3 m o l e N a O H$ in 1 Litre.
Moles of $N a O H$ in $5.0 L = 0.3 \times 5.0 = 1.5 m o l e s$
On mixing the solution
Total moles $= 3.7 + 1.5 = 5.2$
Total volume $= 3.7 + 5 = 8.7$ litre
Molarity of the solution = $\frac{5.2}{8.7}$
$= 0.59 M$

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