Question

Fill in the blank to make the statement true .

${\text{a}}^3{\text{×a}}^{-10}\text{=\_\_.}$

Answer 1

Here we use law of exponents that if bases are same then exponents will be added .

${\text{a}}^{\text{m}}{\text{×a}}^{\text{n}}{\text{=a}}^{\text{m+n}}$

${\text{a}}^3{\text{×a}}^{-10}{\text{=a}}^{3-10}{\text{=a}}^{-7}$

Here $\text{a}$ is the base and $3,-10$ are the exponents .

Hence, ${\text{a}}^{-7}$ is the required answer .