A 3 cm high object is placed at a distance of 80 cm from a concave lens of focal length 20 cm. The position of the image is:

-16 cm

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16 cm

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26.33 cm

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-26.33 cm

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Solution

The correct option is A -16 cm
Here, $u = - 80 c m, f = - 20 c m$

Using the len's formula, $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$

$\frac{1}{v} - \frac{1}{- 80} = \frac{1}{- 20}$

$v = - 16 c m$

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A 3 cm high object is placed at a distance of 80 cm from a concave lens of focal length 20 cm. Find the position and size of the image.

At what point a real image and virtual image are formed? A 3 cm high object is placed at a distance of 80 cm from a concave lens of focal length 20 cm. Find the position and size of the image. [5 MARKS]

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Q. An object is placed at a distance of

100 c m

from a concave lens of focal length

40 c m

. Find the distance of the position of image from the lens in

c m

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A 3 cm high object is placed at a distance of 80 cm from a concave lens of focal length 20 cm. The position of the image is:

The correct option is A -16 cmHere, u=−80cm,f=−20cm Using the len's formula, 1v−1u=1f 1v−1−80=1−20 v=−16cm

The correct option is A -16 cm
Here, $u = - 80 c m, f = - 20 c m$

Using the len's formula, $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$

$\frac{1}{v} - \frac{1}{- 80} = \frac{1}{- 20}$

$v = - 16 c m$