A 3 cm high object is placed at a distance of 80 cm from a concave lens of focal length 20 cm. Find the size of the image.
0.6 cm
Here, u=−80 cm,f=−20 cm
Using the len's formula, 1v−1u=1f
1v−1−80=1−20
v=−16 cm
Magnification, m=h′h=vu=−16−80=15
h′=h5=3.05=0.6 cm
Length of the image is 0.6 cm. Positive sign shows that the image is erect.