You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Understanding of Field

A 3 kg mass...

Question

A $3 k g$ mass and a $4 k g$ mass are placed on $x$ and $y$ axes at a distance of $1 m$ from the origin, and a $1 k g$ mass is placed at the origin. Then the resultant gravitational force on $1 k g$ mass is

7 G

No worries! We‘ve got your back. Try BYJU‘S free classes today!

G

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 G

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 G

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $5 G$
$_{1} = \frac{G \times 1 \times 3}{1}^i$

$_{2} = \frac{G \times 1 \times 4}{1}^j$
Therefore the resultant gravitational force is:
$\to F =_{1} +_{2}$
$| \to F | = \sqrt{{F_{1}}^{2} + {F_{2}}^{2}}$
$= 5 G$

Suggest Corrections

Similar questions

Q. Particles of mass

1 kg

each are placed along

x -

axis at

x = 1, 2, 4, 8, . . . . . \infty

. Then gravitational force on a mass of

3 kg

placed at origin is (

G =

universal gravitational constant)

Q. Mass particles of

1 kg

each are placed along

x -

axis at

x = 1, 2, 4, 8, . . . . . \infty

. Then gravitational force on a mass of

3 kg

placed at origin is (

G =

universal gravitational constant)

A body of mass 1 kg is placed at a distance of 2 m from another body of mass 10 kg. At what distance from the body of mass 1 kg, another body of mass 5 kg must be placed so that the net gravitational force acting on the body of mass 1 kg is zero?

Q. Two particles each of mass

1 K g

are placed at

p

and

Q

such that

P Q = O Q = L

. The gravitational force experienced by another

1 K g

mass placed at

R

, where

O R = L

Four particles of masses 1 kg, 2 kg, 3 kg and 4 kg are placed at the corners of a square of side 2 m in the x-y plane as shown in the figure. If the origin of the coordinate system is taken at the mass of 1 kg, the (x, y) co-ordinates of the centre of mass are

Join BYJU'S Learning Program

A 3kg mass and a 4kg mass are placed on x and y axes at a distance of 1m from the origin, and a 1kg mass is placed at the origin. Then the resultant gravitational force on 1kg mass is

The correct option is C 5G→F1=G×1×31^i →F2=G×1×41^jTherefore the resultant gravitational force is:→F=→F1+→F2|→F|=√F12+F22 =5G

A $3 k g$ mass and a $4 k g$ mass are placed on $x$ and $y$ axes at a distance of $1 m$ from the origin, and a $1 k g$ mass is placed at the origin. Then the resultant gravitational force on $1 k g$ mass is

The correct option is C $5 G$
$_{1} = \frac{G \times 1 \times 3}{1}^i$

$_{2} = \frac{G \times 1 \times 4}{1}^j$
Therefore the resultant gravitational force is:
$\to F =_{1} +_{2}$
$| \to F | = \sqrt{{F_{1}}^{2} + {F_{2}}^{2}}$
$= 5 G$