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Molarity

A 3 M 3L solu...

Question

A 3 M 3L solution of NaOH is mixed with another 3M 5L solution of $N a O H$ . How much should the mixture be diluted so that the final molarity of the solution becomes 1M?

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Solution

$M_{3} V_{3} = M_{1} V_{1} + M_{2} V_{2}$

$M_{3} = \frac{M_{1} V_{1} + M_{2} V_{2}}{V_{1} + V_{2}} = \frac{(3 \times 3) + (3 \times 5)}{3 + 5} = 3 M$

$M_{3} V_{3} = M_{4} V_{4}$

$⟹ 3 \times 8 L = 1 \times V_{4}$

$⟹ 24 L = V_{4}$

$∴ V_{4} = 24 L$

The mixture should be diluted by $= 24 L - 8 L = 16 L$

So, the mixture should be diluted by 16 L to make a solution of 1 M.

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