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Question

A 3-phase balanced load which has a power factor of 0.707 is connected to a balanced supply. The power consumed by the load is 5 kW. The power is measured by the two-wattmeter method. The readings of the two wattmeters are

A
3.94 kW and 1.06 kW
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B
2.50 kW and 2.50 kW
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C
5.00 kW and 0.00 kW
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D
2.96 kW and 2.04 kW
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Solution

The correct option is A 3.94 kW and 1.06 kW
p.f.=0.707,ϕ=cos1(0.707)=45
P=5kW
W1+W2=5...(i)
tanϕ=3(W1W2)(W1+W2)
(W1+W2)×1=3(W1W2)
W1W2=53...(ii)
Form equation (i) and (ii),
W1=3.94kW
W2=1.06kW

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