A 3-phase full converter- fed from 3-phase- 400 V- 50 Hz source is connected to load R - 10 - and large inductance so that output current is ripple free- If firing angle is 45- the reactive power Q is kVAR-

We know that V_0=3V_mlπcosα =3√(2)× 400πcos45^∘ =381.97 V I_0=381.9710=38.197 A Reactive power = V_0I_0tanα = 381.97 × 38.197 tan45^∘ Q = 14590.18 VAR = 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

3-Phase Full Wave Rectifiers

A 3-phase ful...

Question

A 3-phase full converter, fed from 3-phase, 400 V, 50 Hz source is connected to load R = 10 $Ω$ and large inductance so that output current is ripple free. If firing angle is $45^{\circ}$ , the reactive power Q is _______ kVAR.

Open in App

Solution

We know that

$V_{0} = \frac{3 V_{m l}}{π} c o s α = \frac{3 \sqrt{2} \times 400}{π} c o s 45^{\circ}$

$= 381.97 V$

$I_{0} = \frac{381.97}{10} = 38.197 A$

Reactive power = $V_{0} I_{0} t a n α$

$= 381.97 \times 38.197 t a n 45^{\circ}$

$Q = 14590.18 V A R = 14.59 k V A R$

Suggest Corrections

Similar questions

Q. A single phase semi-converter connected to 230 V, 50 Hz source is feeding a highly inductive load R=10

Ω

, L= 3 mH. The load current is ripple free. For the firing angle of

30^{0}

, the reactive power input is

Q. A single-phase semi-converter connected to 230 V, 50 Hz source is feeding a load R =

10 Ω

in series with a large inductance that makes the load current ripple free. The firing angle is

30^{\circ}

, then the current distortion factor is __________

Q. A single-phase semiconverter is connected to 400 V, 50 Hz source. The converter is feeding a load of

R = 50 Ω

in series with large inductor which makes the load current ripple free. If the value of firing angle is 30°, then current distortion factor will be _____________.

Q. A single phase semi converter, connected to 230 V, 50 Hz source is feeding a load

R = 40 Ω

in series with large inductor that makes the load current ripple free. If the value of firing angle is

45^{o}

, then the current distortion factor is

Q. A single-phase semi-converter, connected to 230 V, 50 Hz is feeding a load of resistance R = 10

Ω

in series with a large inductance that makes the load current ripple free. For a firing angle of

45^{o}

, the value of percentage rectification efficiency will be

Join BYJU'S Learning Program

A 3-phase full converter, fed from 3-phase, 400 V, 50 Hz source is connected to load R = 10 Ω and large inductance so that output current is ripple free. If firing angle is 45∘, the reactive power Q is _______ kVAR.

We know that V0=3Vmlπcosα=3√2×400πcos45∘ =381.97V I0=381.9710=38.197A Reactive power = V0I0tanα =381.97×38.197tan45∘ Q=14590.18VAR=14.59kVAR

A 3-phase full converter, fed from 3-phase, 400 V, 50 Hz source is connected to load R = 10 $Ω$ and large inductance so that output current is ripple free. If firing angle is $45^{\circ}$ , the reactive power Q is _______ kVAR.

We know that

$V_{0} = \frac{3 V_{m l}}{π} c o s α = \frac{3 \sqrt{2} \times 400}{π} c o s 45^{\circ}$

$= 381.97 V$

$I_{0} = \frac{381.97}{10} = 38.197 A$

Reactive power = $V_{0} I_{0} t a n α$

$= 381.97 \times 38.197 t a n 45^{\circ}$

$Q = 14590.18 V A R = 14.59 k V A R$