A 3- $ϕ$ inverter as shown in figure is operating in 180 $^{o}$ conduction mode. Assuming all the devices to be ideal, power consumed by the three phase load is

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Solution

In 180 $^{o}$ mode
$Output line voltage, V_{L} = \sqrt{\frac{2}{3}} V_{s}$

$Phase voltage V_{p h} = \frac{V_{L}}{\sqrt{3}} = \frac{\sqrt{2} V_{s}}{3}$

$V_{p h} = \frac{\sqrt{2}}{3} \times 600 = 282.82 V$
Power consumed by 3- $ϕ$ load,

$P = \frac{3 V_{p h}^{2}}{R} = \frac{3 (282.84)^{2}}{80}$
= 3000 W = 3 kW

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A 3-ϕ inverter as shown in figure is operating in 180o conduction mode. Assuming all the devices to be ideal, power consumed by the three phase load is

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A 3- $ϕ$ inverter as shown in figure is operating in 180 $^{o}$ conduction mode. Assuming all the devices to be ideal, power consumed by the three phase load is