A 30 cm diameter pipe conveys water in turbulent flow regime. The friction factor has been estimated as 0.02 for this flow. If the centre line velocity is measured as 3.57 m/s, what is the discharge in the pipe ?
um−Vu∗=3.75
f=0.02
u∗=V×√f8=V×√0.028=0.05 V
um−V=3.75×0.05V
um−V=0.1875 V
um=1.1875 V
3.57=1.1875 V
V=3 m/s
Discharge,Q=A×V=π4×(0.3)2×3=0.212 m3/s