You visited us 2 times! Enjoying our articles? Unlock Full Access!

Specific Heat

A 30 g copper...

Question

A $30 g$ copper is heated at $200^{\circ} C$ with $2550 J$ of energy. The specific heat of the copper will be.

0.425 J / g^{\circ} C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.322 J / g^{\circ} C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.35 J / g^{\circ} C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0.425 J / g^{\circ} C$
Given,
Mass, $m = 30 g = 3 \times 10^{- 2} k g$
Change in temeprature, $Δ T = 200^{\circ} C$
Energy supplied, $Q = 2550 J$
Let $c$ be the specific heat.
We know,
$Q = m c Δ T$
That is, $2550 = 3 \times 10^{- 2} \times c \times 200$
$\Rightarrow c = 425 J / k g^{\circ} C$
$c = 0.425 J / g^{\circ} C$

Suggest Corrections

Similar questions

200 g

200^{o} C

20^{o} C

0.4 J / g^{o} C

i n J

5

20^{\circ}

80^{\circ}

0.092 c a l / g^{\circ} C

1 kg

- 10^{\circ} C

4.4 kg

30^{\circ} C

= 0.5 {cal/g}^{\circ} C

= 1 {cal/g}^{\circ} C

= 80 cal/g

0.385

^{o} C

34.2

25^{o}

4.689

100^{\circ} C

25^{\circ} C

g^{- 1}^{\circ} C^{- 1}

Join BYJU'S Learning Program