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Question

A 30 kW, 3-phase induction motor has full load slip of 3%, the stator losses amounts to 5% of the input and mechanical losses 1.5% of output. If the current in each rotor phase is 45 A, then the resistance per phase of the rotor is ________Ω.(Answer upto three decimal)
  1. 0.155

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Solution

The correct option is A 0.155

Given, Slip, s = 0.03

Per phase output power,
P0=303=10 kW

Now, Mechanical losses =10×1.5100=0.15 kW

Mechanical developed power = 10.15~kW

Rotor copper loss = s× (air gap power)

or Rotor copper loss =s(Mechanical developed power )1s

Pcu(rotor)=0.030.97×10.15=0.3139 kW

I2R=0.3139 kW

Rotor resistance / phase,

R=0.03139×100045×45=0.155 Ω

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