A 30% solution of X at 298 K is marked as saturated solution of X. What is solubility of X at 298 K?

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Solution

Answer:
Solubility:
The maximum amount of solute that can be dissolved in a specified amount of solvent at a specific temperature is known as solubility.
Once the concentration of solute is equal to its solubility, the solution is said to be saturated with that solute and the concentration stops increasing.
$A 30 % s o l u t i o n m e a n s 30 g s o l u t e i s p r e s e n t i n 100 g s o l u t i o n . S o, M a s s o f s o l v e n t (w a t e r) = M a s s o f s o l u t i o n - M a s s o f s o l u t e S o, M a s s o f w a t e r = 100 - 30 g = 70 g S o l u b i l i t y % = \frac{M a s s o f s o l u t e}{M a s s o f s o l v e n t} \times 100 = \frac{30}{70} \times 100 S o l u b i l i t y o f X = 42.85 %$
Conclusion:
The solubility of X is $42.85 %$ .

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