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Question

A 300 g, 30% (w/w) NaOH solution is mixed with 500 g 40% (w/w) NaOH solution. What is the molality of final solution?

A
1.422 m
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B
14.22 m
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C
15.22 m
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D
None
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Solution

The correct option is B 14.22 m
Mole = Total MassMolar mass
Mole of solute (NaOH) =29040=7.25
Mass of solvent = Total mass - Mass of solute =800290=510 g
Molality = Moles of soluteMass of solvent in kg
=7.25510×1000=14.22 m

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